This problem exercises the basic concepts of game playing, using tictactoe (noughts and crosses) as an example. We define $X_n$ as the number of rows, columns, or diagonals with exactly $n$ $X$’s and no $O$’s. Similarly, $O_n$ is the number of rows, columns, or diagonals with just $n$ $O$’s. The utility function assigns $+1$ to any position with $X_3=1$ and $1$ to any position with $O_3 = 1$. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as ${Eval}(s) = 3X_2(s) + X_1(s)  (3O_2(s) + O_1(s))$.

Approximately how many possible games of tictactoe are there?

Show the whole game tree starting from an empty board down to depth 2 (i.e., one $X$ and one $O$ on the board), taking symmetry into account.

Mark on your tree the evaluations of all the positions at depth 2.

Using the minimax algorithm, mark on your tree the backedup values for the positions at depths 1 and 0, and use those values to choose the best starting move.

Circle the nodes at depth 2 that would not be evaluated if alpha–beta pruning were applied, assuming the nodes are generated in the optimal order for alpha–beta pruning.