Explain what is wrong with the following proposed definition of the set membership predicate
$$ {\forall,x,s;;} x \in {x|s} $$ $$ {\forall,x,s;;} x \in s \implies {\forall,y;;} x \in {y|s} $$

Explain what is wrong with the following proposed definition of the set membership predicate
$$ {\forall,x,s;;} x \in {x|s} $$ $$ {\forall,x,s;;} x \in s \implies {\forall,y;;} x \in {y|s} $$





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